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1968 CONCACAF Champions' Cup

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1968 CONCACAF Champions' Cup
Tournament details
Dates26 May – 1 December 1968
Teams10
Final positions
ChampionsMexico Toluca (1st title)
1967
1969

The 1968 CONCACAF Champions' Cup was the 4th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's football club champion in the CONCACAF region.

The tournament was played by 10 teams of 10 nations: Netherlands Antilles, Bermuda, El Salvador, United States, Guatemala, Mexico, Honduras, Suriname, Nicaragua, Costa Rica.

It was played from 26 May till 1 December 1968 under the home/away match system. The tournament was split in 3 zones (North American, Central American and Caribbean), each one qualifying the winner to the final tournament, where the winners of the Central and Caribbean zones played a semi-final to decide who was going to play against the Northern champion in the final. The final was scratched and Toluca were declared champions after both semi-finalists, Aurora and Transvaal, were ejected from the competition (Aurora due to crowd violence and Transvaal for using ineligible players).

Club Deportivo Toluca (actually known as Deportivo Toluca FC) from Mexico thus became for the first time in its history CONCACAF champion.[1][2]

Caribbean zone

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22 April 1968 1st leg Scherpenheuvel Netherlands Antilles 1–1 Suriname (Kingdom of the Netherlands) Transvaal
TBD TBD
2 May 1968 2nd leg Transvaal Suriname (Kingdom of the Netherlands) 3–1 Netherlands Antilles Scherpenheuvel
TBD
TBD
TBD
TBD
  • Transvaal won 4–2 on aggregate score.

Northern zone

[edit]

First round

[edit]
  • NY Greek Americans won 4–3 on aggregate score.

Second round

[edit]
29 September 1968 1st leg Toluca Mexico 4–1 United States NY Greek Americans Mexico
CST Amaury Epaminondas 14' 85' (pen.)
Felipe Ruvalcaba 25'
Francisco Linares 59'
Tonorezos 33' (pen.)
  • Toluca won 7–3 on aggregate score.

Central American Zone

[edit]

First round

[edit]

Torneo Centroamericano de Concacaf 1968

3 April 1968 1st leg Alajuelense Costa Rica 0–2 Guatemala Aurora San José, Costa Rica
CST Oscar Molina
Jorge Roldán
Stadium: Estadio Nacional de Costa Rica
  • Aurora won 2–1 on aggregate score.
21 April 1968 1st leg Alianza El Salvador 1–2 Honduras Olimpia San Salvador, El Salvador
CST Odir Jacques Ricardo Taylor
Donaldo Rosales
Stadium: Estadio Flor Blanca
28 April 1968 2nd leg Olimpia Honduras 1–0 El Salvador Alianza Tegucigalpa, Honduras
CST Conrado Flores Stadium: Estadio Nacional Chelato Uclés
  • Olimpia won 3–1 on aggregate score.

Second round

[edit]
3 November 1968 1st leg Olimpia Honduras 1–1 Guatemala Aurora Tegucigalpa, Honduras
CST TBD TBD Stadium: Estadio Nacional Chelato Uclés
10 November 1968 2nd leg Aurora Guatemala 4–0 Honduras Olimpia Guatemala City, Guatemala
CST TBD
TBD
TBD
TBD
Stadium: Estadio Doroteo Guamuch Flores
  • Aurora won 5–1 on aggregate score.

Semi-final

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27 November 1968 1st leg Transvaal Suriname (Kingdom of the Netherlands) 1–1 Guatemala Aurora Paramaribo, Dutch Guiana
AST Swie TBD
1 December 1968 2nd leg Aurora Guatemala 0–2 Suriname (Kingdom of the Netherlands) Transvaal Paramaribo, Dutch Guiana
AST Nil TBD
TBD

The semi-final was declared null and void, and both teams were ejected from the competition: Aurora after their fans invaded the pitch following the end of the 2nd leg and caused a mass brawl between celebrating Transvaal fans, and Transvaal for using three ineligible players in both legs.

Final

[edit]

After Aurora and Transvaal were both ejected from the competition, the final was scratched and Toluca were declared champions.[1]

Champion

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 CONCACAF Champions' Cup
1968 champion 
Mexico
Toluca
1st title

References

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  1. ^ a b Copa de Campeones 1968 on the RSSSF
  2. ^ Todos los campeones de Concacaf on Goal.com, 20 Dec 2020